X^2+60x-4000=0

Solution for X^2+60x-4000=0 equation:

X^2+60X-4000=0

a = 1; b = 60; c = -4000;
Δ = b2-4ac
Δ = 602-4·1·(-4000)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-140}{2*1}=\frac{-200}{2}
=-100
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+140}{2*1}=\frac{80}{2}
=40
$